Compound Inequalities

Introduction

Compound inequalities allow us to describe ranges of values using two inequalities at once.
They come in two main types:

You should already feel comfortable solving multi-step inequalities such as
$3x - 5 \le 10$ or $-2(x + 4) > 6$.
Now we extend those skills to situations where two inequalities work together.

What Is a Compound Inequality?

A compound inequality combines two separate inequalities using:

Examples:

Solving AND Compound Inequalities

1. The “Sandwich” Method

Some AND inequalities appear as a single combined statement: $$a < bx + c \le d$$ To solve:

Example: $$-4 \le 2x + 6 < 10$$

2. The “Two Inequalities” Method

Sometimes the inequality is written separately:

Example: $$x - 3 > 1 \text{ and } 2x + 1 \le 9$$

Overlap: no values satisfy both → no solution.

Solving OR Compound Inequalities

For OR inequalities:

Example: $$3x - 2 < 4 \text{ OR } x + 5 \ge 12$$

Final solution: $$x < 2 \text{ OR } x \ge 7$$

Graphing Compound Inequalities

AND (Intersection)

OR (Union)

Graphing Tips

Both types of compound inequalities on a number line

Common Mistakes to Avoid

Exercises

  1. Solve the compound inequality: $-3 < 2x + 1 \le 7$

    Solution

    Solve $-3 < 2x + 1 \le 7$

    • Subtract 1: $-4 < 2x \le 6$
    • Divide by 2: $-2 < x \le 3$

    Solution: $(-2, 3]$

  2. Solve: $x - 4 > 3$ AND $2x + 1 \le 11$

    Solution

    %$x - 4 > 3$ AND $2x + 1 \le 11$$

    • First: $x > 7$
    • Second: $2x \le 10 \Rightarrow x \le 5$

    No overlap → no solution.

  3. Solve the OR inequality: $5x - 2 \ge 13$ OR $-x + 1 < -4$

    Solution

    $$5x - 2 \ge 13$ OR $-x + 1 < -4$$

    • First: $5x \ge 15 \Rightarrow x \ge 3$
    • Second: $-x < -5 \Rightarrow x > 5$

    Union: $x \ge 3$

  4. Determine whether the inequality set has a solution:
    $3x + 6 < 0$ AND $x - 2 \ge 5$

    Solution

    $$3x + 6 < 0$ AND $x - 2 \ge 5$$

    • First: $3x < -6 \Rightarrow x < -2$
    • Second: $x \ge 7$

    No overlap → no solution.

  5. Write the solution set of $x < -2$ OR $x \ge 6$ in interval notation.

    Solution

    $$x < -2$ OR $x \ge 6$$ Interval notation: $$(-\infty, -2) \cup [6, \infty)$$

  6. Solve: $-8 \le -2x + 4 < 6$

    Solution

    $$-8 \le -2x + 4 < 6$$

    • Subtract 4: $-12 \le -2x < 2$
    • Divide by $-2$ (flip signs): $$6 \ge x > -1$$

    Rewrite in standard order: $$-1 < x \le 6$$

  7. Solve: $x + 3 > 10$ OR $4 - x \le -1$

    Solution

    $$x + 3 > 10$ OR $4 - x \le -1$$

    • First: $x > 7$
    • Second: $-x \le -5 \Rightarrow x \ge 5$

    Union: $x \ge 5$